How to 'flip/reverse' the signal?
13 ビュー (過去 30 日間)
古いコメントを表示
Hi all,
I have a signal like this (attached). This is sensor orientation data in z dimension during human walking.

I am extracting parts of the signal between red vertiical lines (precisely between first 8 and last 8 pairs of the lines).
When I plot all of them over one figure I get this.
hold on
for i = 1:length(S_or_z_cycle)
plot(S_or_z_cycle{i},'r') ;
title('Shank orientation Z'); xlabel('% of movement cycle'); ylabel('degrees')
end

Is there a way to "flip/reverse" the signal below 0 so it aligns with the signal above 0, remaining its shape? When I apply "-" I get this which is not what I want as it changes the shape of the signal.

Wheareas I want something like this:

1 件のコメント
Mathieu NOE
2022 年 3 月 9 日
編集済み: Mathieu NOE
2022 年 3 月 9 日
hello Tomaszzz
seems you want to apply a vertical shift of the negative data so they overlay with the positive ones
this shift is computed by taking the mean of the negative curves minus the mean of the positive curves
採用された回答
その他の回答 (0 件)
参考
カテゴリ
Help Center および File Exchange で Parametric Spectral Estimation についてさらに検索
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!