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how to read text file into formatted array

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H D
H D 2014 年 12 月 15 日
コメント済み: H D 2014 年 12 月 15 日
Hi
I have a text file which contains many rows of this shape
'0862;1;10/09/2002;09:15:59;23.845089;38.018470;486253.80;4207588.10'
I need to read each line in different cells. each cell contains data between ";" and the third and forth one are date and time while others are double numbers.
would you please help me to do so
  2 件のコメント
per isakson
per isakson 2014 年 12 月 15 日
編集済み: per isakson 2014 年 12 月 15 日
"I need to read each line in different cells" &nbsp Why is that? And what does it exactly mean?
H D
H D 2014 年 12 月 15 日
thanks for comment. I need to read the whole txt file in a matrix. I presented the first line as a sample. each cell data is separated using semicolon as mentioned. in this case third and forth are date and time of day and all the rest can be saved as double in a matrix.

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per isakson
per isakson 2014 年 12 月 15 日
編集済み: per isakson 2014 年 12 月 15 日
Here is a function, which does what I believe is what you want. The third column of out is a serial date number.
>> out = cssm('cssm.txt')
out =
1.0e+06 *
0.0009 0.0000 0.7315 0.0000 0.0000 0.4863 4.2076
0.0009 0.0000 0.7315 0.0000 0.0000 0.4863 4.2076
0.0009 0.0000 0.7315 0.0000 0.0000 0.4863 4.2076
>> datestr( out(:,3), 31 )
ans =
2002-10-09 09:15:59
2002-10-09 09:15:59
2002-10-09 09:15:59
where
function out = cssm( filespec )
fid = fopen( filespec );
cac = textscan( fid, '%f%f%s%s%f%f%f%f' ...
, 'Delimiter',';', 'CollectOutput',true );
fclose( fid );
str = cell2mat(cac{2});
sdn = datenum( str, 'mm/dd/yyyyHH:MM:SS');
out = cat( 2, cac{1}, sdn, cac{3} );
end
and where cssm.txt contains
0862;1;10/09/2002;09:15:59;23.845089;38.018470;486253.80;4207588.10
0862;1;10/09/2002;09:15:59;23.845089;38.018470;486253.80;4207588.10
0862;1;10/09/2002;09:15:59;23.845089;38.018470;486253.80;4207588.10
  4 件のコメント
per isakson
per isakson 2014 年 12 月 15 日
編集済み: per isakson 2014 年 12 月 15 日
cssm is the function defined after the word, where, in my answer.
H D
H D 2014 年 12 月 15 日
:D sorry for my crazy question. you are right. It works perfectly. thanks

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その他の回答 (1 件)

Azzi Abdelmalek
Azzi Abdelmalek 2014 年 12 月 15 日
編集済み: Azzi Abdelmalek 2014 年 12 月 15 日
fid=fopen('FileName.txt')
tline = fgetl(fid)
out=[];
while ischar(tline)
out{end+1,1} =tline
tline= fgetl(fid);
end
fclose(fid)
%You can aadd
A=regexp(out,';','split')
n=numel((A{1}))
B=reshape([A{:}],n,[])'
res=[cell

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