Select August data from a vector column in the format YYYYMMDD
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Hi,
I have two vector columns, one containing the dates in the format YYYYMMDD for 10 years, and in the other column the amount of rainfall in mm. I want to create a matrix, or two vector columns, containing only the months of august with the corresponding rainfall. Any ideas how to achieve this?
Thanks in advance
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採用された回答
Roger Wohlwend
2014 年 12 月 11 日
First convert your time vector into a vector that contains the date as a number.
Date = datenum(Date_Vector,'YYYYMMDD');
Now search for August.
q = month(Date) == 8;
Create your matrix.
AugustRainfallMatrix = [Date(q), Rainfall(q)];
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その他の回答 (1 件)
Peter Perkins
2014 年 12 月 11 日
編集済み: Peter Perkins
2014 年 12 月 11 日
Are the dates strings, or numbers?
If you have access to R2014b, you could do either of these, depending on which you have:
>> c % cell array of strings
c =
'20141201'
'20141202'
'20141203'
'20141204'
'20141205'
>> month(datetime(c,'Format','yyyyMMdd'))
ans =
12
12
12
12
12
>> x % integer values
x =
20141201
20141202
20141203
20141204
20141205
>> month(datetime(x,'convertFrom','YYYYMMDD'))
ans =
12
12
12
12
12
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