Array as input for symbolic function

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cdlapoin
cdlapoin 2022 年 2 月 27 日
コメント済み: cdlapoin 2022 年 2 月 27 日
this is an quation for the Mach number as a function of location and area ratio
so I create an array of area ratios and want to examine M
A_ratio = (0:1:100);
gamma = 1.4;
syms M
eq1 = A_ratio == ((gamma+1)/2)^((gamma+1)/(2*(gamma-1)))*((1+(gamma-1)/2*M^2)^((gamma+1)/(2*(gamma-1)))/M)
eq1 = 
var = vpa(eq1)
var = 
double(var)
ans = 1×101
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
here the symbolic output of vpa looks correct (non-zero), but when I try to change back from symbolic to numeric array the result is all zeros. is double() the wrong command for this? I am referencing: https://www.mathworks.com/help/symbolic/conversion.html
is there a smarter way to do this?

採用された回答

Torsten
Torsten 2022 年 2 月 27 日
gamma = 1.4;
syms A_ratio M
eq1 = A_ratio == ((gamma+1)/2)^((gamma+1)/(2*(gamma-1)))*((1+(gamma-1)/2*M^2)^((gamma+1)/(2*(gamma-1)))/M);
sol = solve(eq1,M);
solnum = subs(sol,A_ratio,1) %e.g.
  1 件のコメント
cdlapoin
cdlapoin 2022 年 2 月 27 日
Thank you,
I didn't expect to get 6 roots, and none of them matched what I know about how the output should look. In the end it was because of a missing (-) sign in my definition of eq1. Once that was corrected I could easily see that the real part of the first root was the correct value I was looking for.

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