How do I plot Sinusoidal wave over a circle in Matlab?

 採用された回答

Arthur Reis
Arthur Reis 2022 年 2 月 22 日

1 投票

I'm not sure if I 100% understood your question, but here it is
t = 0:0.01:2*pi; %define interval
x = cos(t);
y = sin(t);
figure;
plot(x,y); %normal circle
%%
f = 10; %define modulation frequency
A = .2; % modulation amplitude
R = A*cos(f*t); %
x = cos(t) + R;
y = sin(t) + R;
figure;
plot(x,y); %similar to your example
%%
x = cos(t).*(1 + R);
y = sin(t).*(1 + R);
figure;
plot(x,y); %modulating the radius

7 件のコメント

loyyy
loyyy 2022 年 2 月 22 日
Hi, thank you for your response. It should be 3 dimensional.
Arthur Reis
Arthur Reis 2022 年 2 月 22 日
like so?
t = 0:0.01:2*pi; %define interval
x = cos(t);
y = sin(t);
f = 10; %define modulation frequency
A = .2; % modulation amplitude
R = A*cos(f*t); %
z = R;
figure;
plot3(x,y,z);
loyyy
loyyy 2022 年 2 月 24 日
Thank you.
Arthur Reis
Arthur Reis 2022 年 2 月 24 日
no problem. If you could please accept an answer so we can close this quesiton.
loyyy
loyyy 2022 年 3 月 6 日
Hi @Arthur Reis! Follow up question. If I want to pick 120 points/vertices in the closed curve (equal distances) and extarct their coordinates. What will be the codes then? Hoping you could help me on this problem, as soon as possible. Thank you very much.
Arthur Reis
Arthur Reis 2022 年 3 月 7 日
Hello,
you'll only need to change the definition of the 't'. You can use linspace to get an linearly spaced array with expecific number of points (120 in this case). So:
tp = linspace(0,2*pi,120); %new array
xp = cos(tp);
yp = sin(tp);
f = 10; %define modulation frequency
A = .2; % modulation amplitude
Rp = A*cos(f*tp); %
zp = Rp;
figure;
scatter3(xp,yp,zp);
Their coordinates are xp, yp, zp.
Does this solve your problem?
loyyy
loyyy 2022 年 3 月 10 日
Yes, Thank you.

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