Creating a submatrix from a matrix

I want a code to create a matrix which consist of rows and columns of another matrix.
i.e. A (4X4) = [ 1 2 3 4; 5 6 7 8; 1 3 5 7; 2 4 6 8; ]
The submatrix B consist of the { 1, 2, 4 }rows of A and the { 2,3 }columns of A:
Β (3Χ2) = [ 2 3; 6 7; 4 6; ]
Any help could be useful.
Thanks in advance!

1 件のコメント

said mohamed
said mohamed 2021 年 5 月 5 日
Using the matrix A = [5 1 11; 7 13 3; 8 5 2], the matrix B is constructed as B = [A A A; A A A; A A A]. Which of the following is the result of the operation K = L * J, made using the submatrices of matrix B, L = B (1: 3,3: 5) and J = B (2: 4,2: 3)?

サインインしてコメントする。

 採用された回答

Azzi Abdelmalek
Azzi Abdelmalek 2014 年 12 月 4 日
編集済み: Azzi Abdelmalek 2014 年 12 月 4 日

10 投票

A= [ 1 2 3 4; 5 6 7 8; 1 3 5 7; 2 4 6 8; ]
B=A([1 2 4],[2 3])

6 件のコメント

Konstantinos
Konstantinos 2014 年 12 月 4 日
Thanks a lot!
Mahadi Hasan
Mahadi Hasan 2019 年 4 月 15 日
thanks a lot brother.
Rajib Das
Rajib Das 2019 年 9 月 9 日
Instead of specifying particular rows and columns can I specify range of rows and columms
Stephen23
Stephen23 2019 年 9 月 9 日
A(2:4,2:3)
Himalsha Dharmapala
Himalsha Dharmapala 2021 年 1 月 25 日
Thanks
said mohamed
said mohamed 2021 年 5 月 5 日
Using the matrix A = [5 1 11; 7 13 3; 8 5 2], the matrix B is constructed as B = [A A A; A A A; A A A]. Which of the following is the result of the operation K = L * J, made using the submatrices of matrix B, L = B (1: 3,3: 5) and J = B (2: 4,2: 3)?

サインインしてコメントする。

その他の回答 (1 件)

VANSHUL CHOUDHARY
VANSHUL CHOUDHARY 2021 年 8 月 20 日

1 投票

A = rand(4,3);
% Get those elements of A that are located in rows 3 to 4 and
% column 2 to 3.
sub_matrix = A(3:4,2:3);

4 件のコメント

Justin Paulan
Justin Paulan 2023 年 11 月 12 日
For example if the matrix is 5x5 and i want to creat a submatrix that is 2x4 it easy to just use how you showed. But i have to creat a submatrix that is 2x4 that has the first 2 rows and columns from the same position in the 5x5 but has the last two rows and columns from the middle position of the 5x5... How do i do that? Matix A is the 5x5 and i wanna get to A4 by using your method.
Dyuman Joshi
Dyuman Joshi 2023 年 11 月 12 日
@Justin Paulan, experiment with the methods shown in the Answers in this thread.
Ioannis Aggelos
Ioannis Aggelos 2024 年 4 月 29 日
wow that was helpful (it wasnt)
Gabriele Bunkheila
Gabriele Bunkheila 2024 年 12 月 3 日
Please note:
  1. With matrices, the first dimesion is always the number of row, the second is the number of columns. So in this case A is 5x5 (size(A) would return [5,5]) and A4 is 4x2 (size(A4) would return [4,2]).
  2. A4 here seems composed of two "stacked" (or vertically concatenated) 2x2 sub-matrices of A
A possible way to obtain A4 from A is the following;
A = [1:5; 0.5*(-10:-6); 0.1*0:4; 10:-1:6; 2*(1:5)]
A = 5×5
1.0000 2.0000 3.0000 4.0000 5.0000 -5.0000 -4.5000 -4.0000 -3.5000 -3.0000 0 1.0000 2.0000 3.0000 4.0000 10.0000 9.0000 8.0000 7.0000 6.0000 2.0000 4.0000 6.0000 8.0000 10.0000
<mw-icon class=""></mw-icon>
<mw-icon class=""></mw-icon>
rows1 = [1, 2];
cols1 = [1, 2];
rows2 = [3, 4];
cols2 = [3, 4];
A4 = [A(rows1, cols1); A(rows2, cols2)]
A4 = 4×2
1.0000 2.0000 -5.0000 -4.5000 2.0000 3.0000 8.0000 7.0000
<mw-icon class=""></mw-icon>
<mw-icon class=""></mw-icon>
@Ioannis Aggelos I hope this helps.

サインインしてコメントする。

カテゴリ

ヘルプ センター および File ExchangeCreating and Concatenating Matrices についてさらに検索

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by