Using regexp to extract data

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M Abdelreheem
M Abdelreheem 2022 年 2 月 19 日
編集済み: DGM 2022 年 2 月 20 日
I am checking a code in which the following line is existed, as an example nNam= n111-y1 therefore I think this line reads all nNam which has this format (n1\d1$)|n1\d1-y,
nid = cellfun(@isempty,regexp(nNam,'(n1\d1$)|n1\d1-y'));
Now, I would like to read different nNam to be as an example nNam= n156, I searched for resources to get the corresponding regexp readible format but I did not find it. Could you help me with this?
Many thanks in advance
  2 件のコメント
Akira Agata
Akira Agata 2022 年 2 月 20 日
Do you want to detect "n + 3 digits" ?
If so, the regular expression will be 'n\d{3}'.
M Abdelreheem
M Abdelreheem 2022 年 2 月 20 日
編集済み: M Abdelreheem 2022 年 2 月 20 日
Thank you so much, it works well! but unfortunately, it detected all the lines started by a letter (n and m), is it applicable to detect points which start only with n1+2numbers+1 like (n1361) ?

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回答 (1 件)

DGM
DGM 2022 年 2 月 20 日
編集済み: DGM 2022 年 2 月 20 日
You haven't clearly stated what you want it to match and not match.
I'm going to assume that you want it to match "n1" followed by zero or more digits, with a trailing sequence consisting either of a single 1 or "1-y".
nNam = {'n111-y1','n156','n256','n1331'};
nid = cellfun('isempty',regexp(nNam,'n1\d*(1|1-y1)'))
nid = 1×4 logical array
0 1 1 0
If there is a restriction on the number of digits in the middle, you'll have to change the quantifier.

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