Mapping Column Vector back into Temporary Array
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Hi,
I have a column vector (temperature) storing 40 values which I would like to transfer into a temporary array, tempm.
The Array is initialised with zeros(6,12). I have been trying to use an example I have to help but in that case the array is NXN (5X5) whereas I have an N and an M, 6 and 12 respectivly and I can't work out how to write the code to reflect this. My best attempt so far is below, however the bottom line should be 0 to 2 in 0.2 intervals and the 12th vector column should be 0 to 1 ascending in 0.2 intervals:
xax = zeros(1,M+2);
yax = zeros(N+2,1);
for i=1:N+2,
xax(i) = (i-1)/(M/2);
yax(i)=(i-1)/(N+1);
tempm(i,M+2) = (i-1)/(M/2);
tempm(N+2,i) = (i-1)/(N+1);
end
Thanks in advance for any help. Please let me know if you require any more information or code.
7 件のコメント
Mike Scott
2014 年 12 月 3 日
Sean de Wolski
2014 年 12 月 3 日
Can you post: your original array temp and what you'd like tempm to be? It's not clear to me where all of the pieces in the for-loop are coming from or what they goals are.
Mike Scott
2014 年 12 月 4 日
編集済み: Mike Scott
2014 年 12 月 4 日
Mike Scott
2014 年 12 月 4 日
Mike Scott
2014 年 12 月 4 日
Star Strider
2014 年 12 月 4 日
You have 72 values in your array and 40 in your vector.
Please describe how you want to map those 40 values to your array.
Mike Scott
2014 年 12 月 4 日
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