function dx = compactchua(t,x)
dx=zeros(4,1);
dx(1) = -(1/(8200*47*1e-9))*x(2);
dx(2) = (((x(3)-x(2))/2000) -(x(4).^3*4.7e3+1e3))/6.8e-9;
dx(3) = ((x(2)-x(3))/2000 - x(4))/68e-9;
dx(4) = (x(3))/(22*10^-9);
end
[t,x] = ode15s(@compactchua,[0 5e-7],[0 12.24e-3 12.24e-3 1.7]);
plot(x(:,2),x(:,3));
error
Warning: Failure at t=6.943264e-08. Unable to meet integration tolerances without reducing the step size below
the smallest value allowed (2.117582e-22) at time t.
>>

2 件のコメント

David Goodmanson
David Goodmanson 2022 年 2 月 16 日
Hi nune,
you might want to double check the equations, especially the signs, because the solution gives the impression of wanting to increase without bound.
Walter Roberson
Walter Roberson 2022 年 2 月 16 日

サインインしてコメントする。

回答 (1 件)

Bhavana Ravirala
Bhavana Ravirala 2022 年 2 月 16 日

0 投票

Hi Pratyusha,
In case of sharp discontinuities in the reference input, it is possible that this warning is generated at intermediate time steps. As it tries to reduce the time step to a small amount in order to counter the abrupt change due to the discontinuity in the reference input.
For sharp discontinuities, it might not be possible to avoid this warning. However, for non-discontinuous inputs we can set relative and absolute tolerance to a higher number than the default setting.
For more information refer the below links:
Hope this helps.

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R2021b

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2022 年 2 月 12 日

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2022 年 2 月 16 日

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