integral calculation size problem

a = 0.6;

% Define pu and pL

PU = 130000*exp(-x./(10*a));

PL = 150000*exp(-x./(10*a));

% integral cal

fun1 = @(x) (PL - PU);

N1 = integral(fun1,0,3*a);

% the matlab shows me a error here (output of function must be same size as input)

% Actually, I am not show where the error is, could you help me to fix it?

Answer 1

[Arif Hoq]

i took the value of x=10, because you did not mention that. you need to mention ArrayValue as true, cause you are using the function as array/vector value

 a = 0.6;
 x=10;
% Define pu and pL
PU = 130000*exp(-x./(10*a));
PL = 150000*exp(-x./(10*a));
% integral cal 
fun1 = @(x) (PL - PU);
N1 = integral(fun1,0,3*a,'ArrayValued', true)

N1 = 6.7995e+03

Answer 2

[Steven Lord]

 a = 0.6;
% Define pu and pL

Make PU and PL functions of x.

PU = @(x) 130000*exp(-x./(10*a));
PL = @(x) 150000*exp(-x./(10*a));
% integral cal 

Call those functions in your integrand.

fun1 = @(x) (PL(x) - PU(x));
N1 = integral(fun1,0,3*a)

N1 = 3.1102e+04