Decimal Matrix to Binary Matrix

Hello,

I am having difficulties in converting a matrix of decimal numbers to its corresponding binary matrix. Here is the problem.

For example, we have a Matrix A;

A=[9 7 15 ; 4 14 8 ]

The range of values in matrix A is from 1 to 16 inclusive. A is in fact an N by 3 matrix. where N is a user-defined integer value. For each decimal number the corresponding binary output should have 5 bits. That is 5 bits per decimal number.

I want the output to be;

Output=[0 1 0 0 1 0 0 1 1 1 0 1 1 1 1 ; 0 0 1 0 0 0 1 1 1 0 0 1 0 0 0]

I tried using the following codes, but it did not work.

A=[9 7 16 ; 4 14 8 ]

x=dec2bin(A');

x=x'; x=str2num(x(:));

 Output=x'

I obtain

Output=[ 0 1 0 0 1 0 0 1 1 1 1 0 0 0 0 0 0 1 0 0 0 1 1 1 0 0 1 0 0 0]

Can you please help me out?

Hope to hear from you very soon.

Thank you in advance.

Regards,

Amit

Answer 1

[Guillaume]

Nearly there. First since you want 5 bits per numbers, you need to tell it to dec2bin:

x = dec2bin(A', 5);

Then to convert a string of 0s and 1s into a matrix of 0s and 1s, just subtract '0' from the string

x = x'; x = x-'0';

It's then a matter of reshaping the output:

output = reshape(x, [], size(A, 1))'

[Amit Sookun]

You are too good! Thank you very much Guillaume!!

Answer 2

[Usman Akhtar]

Thanks