What is the problem in simple matrix operation.?
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clear all;clc
names = {'A'; 'B'; 'C'; 'D'};
marks = [27; 48; 84; 22];
in_st = {names marks};
in_st = [names num2cell(marks)];
function [op_st1,op_st2] = print_Data(in_st)
in_st = in_st;
[~,idx] = sort(in_st(:,1));
op_st1 = in_st(idx,:)
[~,idx] = sort(in_st(:,2),'descend');
op_st2 = in_st(idx,:)
I want op_st1 in ascending order, and op_st2 in descending order. It works well upto half program, what is the problem in remaining..?
2 件のコメント
採用された回答
Guillaume
2014 年 11 月 23 日
As the error message says and the documentation of sort states, you can't use the DIM and MODE arguments when sorting cell arrays.
However, since the descending order is just the reverse of the ascending order, why don't you just flip your first sort?
[~, idx] = sort(in_st(:, 1));
op_st1 = in_st(idx, :);
op_st2 = in_st(flipud(idx), :);
2 件のコメント
Guillaume
2014 年 11 月 23 日
Oh, yes, sorry, I missed that. You can still reverse do what I said but on column 2:
[~, idx] = sort(in_st(:, 2));
op_st2 = in_st(flipud(indx), :);
Or you could convert column 2 to matrix:
[~, idx] = sort(cell2mat(in_st(:, 2)), 'descend');
その他の回答 (1 件)
Azzi Abdelmalek
2014 年 11 月 23 日
編集済み: Azzi Abdelmalek
2014 年 11 月 23 日
Use curly brackets { }
[~,idx] = sort(in_st{:,2},'descend')
3 件のコメント
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