need to read a mixed csv file
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I would like to read the csv file attached and generate the following variables
MAIN_FOLDER ="V:\OPTIMIZATION_DEPOT\AntGod\"
SUB_FOLDER="V:\OPTIMIZATION_DEPOT\AntGod\AntGODorig_20211223_0528\O_20220110_0614_Yaqing_Optimization_OMEGA002\"
MACHINE="V:\ "
PROJECT_NAME="20220110_0614_Yaqing_Optimization"
Variable_Names =[ "sk_outer_polyrod" "sk_inner_polyrod" "sk" "n_offset" "k15" "k14" "k13" "k12" "k11" "k10 "]; (strings)
Variable_Units =[ "Nan" "Nan" "mm" "mm" "mm" "mm" "mm" "mm" "mm" "mm" ]; (strings)
Initial_Value =[0.75 0.85 0.08 5 15 32 61 91 86 80 ]; (floating numbers)
Minimum_Value =[ 0.7 0.7 0.06 3.75 11.25 24 45.75 68.25 64.5 60 ]; (floating numbers)
Maximal_Value =[ 1.5 1.4 0.3 7 20 42 80 120 120 110 ] (floating numbers)
I really would like to have this in csv format so I can easily edit it with either microsoft excel or Libreoffice calc. It's supposed to be an input file for an optimization setup. I tried many options (readcsv, readxlsx,csv2struct, etc) but none of them allowed me to achieve this
Thank you
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その他の回答 (2 件)
Image Analyst
2022 年 1 月 29 日
Try this:
data = readcell('test.csv')
% MAIN_FOLDER ="V:\OPTIMIZATION_DEPOT\AntGod\"
% SUB_FOLDER="V:\OPTIMIZATION_DEPOT\AntGod\AntGODorig_20211223_0528\O_20220110_0614_Yaqing_Optimization_OMEGA002\"
% MACHINE="V:\ "
% PROJECT_NAME="20220110_0614_Yaqing_Optimization"
% Variable_Names =[ "sk_outer_polyrod" "sk_inner_polyrod" "sk" "n_offset" "k15" "k14" "k13" "k12" "k11" "k10 "]; (strings)
% Variable_Units =[ "Nan" "Nan" "mm" "mm" "mm" "mm" "mm" "mm" "mm" "mm" ]; (strings)
% Initial_Value =[0.75 0.85 0.08 5 15 32 61 91 86 80 ]; (floating numbers)
% Minimum_Value =[ 0.7 0.7 0.06 3.75 11.25 24 45.75 68.25 64.5 60 ]; (floating numbers)
% Maximal_Value =[ 1.5 1.4 0.3 7 20 42 80 120 120 110 ] (floating numbers)
SUB_FOLDER = data{2,2}
slashLocations = strfind(SUB_FOLDER, '\')
MAIN_FOLDER = SUB_FOLDER(1:slashLocations(3))
MACHINE = data{3, 2}
PROJECT_NAME = data{4, 2}
Variable_Names = data(6 : 15);
Variable_Units = data(6 : 15, 2);
for row = 6 : 15
Initial_Value(row - 5) = data{row, 3};
Minimum_Value(row - 5) = data{row, 4};
Maximal_Value(row - 5) = data{row, 5};
end
fprintf('Done!\n');
4 件のコメント
NAFTALI HERSCOVICI
2022 年 1 月 29 日
NAFTALI HERSCOVICI
2022 年 1 月 29 日
Image Analyst
2022 年 1 月 29 日
編集済み: Image Analyst
2022 年 1 月 29 日
I literally used the file you attached and it worked fine. So you must be trying it on a different file that has a different format, like the things are in different locations, or there are extra things in the file, or things missing. Attach that file and we'll see how to make the code more flexible, within reason.
The error tells me that what's in data(row, 3) is not a single number like the example you uploaded. What is it? A vector? A matrix?
NAFTALI HERSCOVICI
2022 年 1 月 30 日
NAFTALI HERSCOVICI
2022 年 1 月 30 日
0 投票
6 件のコメント
Image Analyst
2022 年 1 月 30 日
There is at least one cell in the data cell array that contains null. writecell() doesn't like that. Scan the array and if the contents are empty, assign it to something, like a space or whatever you want.
for k = 1 : numel(data)
if isempty(data{k})
data{k} = ' ';
end
end
NAFTALI HERSCOVICI
2022 年 1 月 30 日
Image Analyst
2022 年 1 月 30 日
I can't do anything unless you upload the file, right? Did you forget to attach it?
NAFTALI HERSCOVICI
2022 年 1 月 30 日
Image Analyst
2022 年 1 月 30 日
Not sure I'll get to it today. Some football games to watch and guests coming over soon.
NAFTALI HERSCOVICI
2022 年 1 月 30 日
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