Time Bandwidth product of Rectangular Waveform is greater than 1

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Sanwal Chaudhry
Sanwal Chaudhry 2022 年 1 月 20 日
回答済み: Hornett 2024 年 9 月 17 日
I am using Pulse Waveform Analyzer which is present in Signal Processing and Communication.
As far as I know the time bandwidth product of a simple rectangular pulse is 1. As the bandwisth is inversely proportional to pulse width. Then why I am not getting 1 in the output. ?

回答 (1 件)

Hornett
Hornett 2024 年 9 月 17 日
Hi Sanwal,
I understand that you are facing issues with the Pulse waveform analyzer, The time-bandwidth product of a signal is a measure of its spread in both the time and frequency domains. For a simple rectangular pulse, the ideal time-bandwidth product is indeed 1, assuming a perfectly rectangular pulse and an idealized system with no distortions or practical limitations.
However, when you're using a practical system like a Pulse Waveform Analyzer in Signal Processing and Communications, there are several factors that can cause the time-bandwidth product to deviate from 1:
  1. Windowing Effects: The analysis of signals often involves windowing, which can spread the signal in the frequency domain. If the pulse is not perfectly rectangular or is windowed (e.g., with a Hamming, Hanning, or Blackman window), the spectral content will be altered, which can affect the time-bandwidth product.
  2. Bandwidth Definition: The bandwidth of a pulse can be defined in different ways (e.g., full width at half maximum, -3 dB points, etc.). The tool you are using may define bandwidth differently from the theoretical definition, leading to different time-bandwidth products.
  3. Discretization and Sampling: In a digital system, signals are sampled and discretized, which can introduce artifacts such as spectral leakage and aliasing. These effects can broaden the frequency spectrum of the pulse.
  4. Filtering and System Response: The Pulse Waveform Analyzer may have its own internal filtering or system response characteristics that affect the signal's frequency content.
  5. Finite Pulse Duration and Rise/Fall Times: A real pulse will have finite rise and fall times, which means it is not a perfect rectangle in the time domain. This can cause additional frequency components that extend the bandwidth.
To investigate why you're not getting a time-bandwidth product of 1, consider the following steps:
  • Check the Analysis Settings: Ensure that the analysis settings match the theoretical assumptions. For example, check if there's any windowing applied and what definition of bandwidth the analyzer uses.
  • Signal Characteristics: Look at the characteristics of the pulse you're analyzing. If it's not a perfect rectangular pulse, you may need to adjust your expectations for the time-bandwidth product.
  • Tool Documentation: Consult the documentation for the Pulse Waveform Analyzer to understand how it calculates the time-bandwidth product and whether there are any settings that could affect the result.
  • Simulation Parameters: If you're simulating the pulse, ensure that the simulation parameters (like the sampling rate and pulse duration) are set up correctly to avoid discretization issues.
  • Compare with Theoretical Pulse: If possible, compare your pulse with a theoretical rectangular pulse and its time-bandwidth product to see if there are any differences in the pulse shapes that could explain the discrepancy.
I hope this information helps

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