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Why does my function not return a figure when there is no error but when there is it returns a figure?

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So i want a function to give me date (value: 1x1 table) as an output and a figure (polarhistogram), but when the function doesnt give an error i wont get a figure. Only when i type some random function with some random variables inside of that function it gives a figure as an output but after that my whole script stops.
So how do i get this line of code below as an output in a figure?
figure
h = polarhistogram (deg2rad(x),deg2rad(y));
Invalid expression. When calling a function or indexing a variable, use parentheses. Otherwise, check for mismatched delimiters.
When simpely demanding h as an output i get this message:
handle to deleted Histogram
The only sections needed to run are 1, 3, 9
But i want this as an output of my function:
Btw windrichtingen means winddirections in dutch.
  7 件のコメント
Walter Roberson
Walter Roberson 2022 年 1 月 14 日
Unrecognized function or variable 'FahrenheitToCelcius'.
Dirk te Brake
Dirk te Brake 2022 年 1 月 14 日
Thanks for all the effort but i found out what the problem was. I plotted another graph without creating a new figure so my polarhistogram disappeard. So only when i created an error I could see the polarhistogram.

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回答 (1 件)

Walter Roberson
Walter Roberson 2022 年 1 月 13 日
編集済み: Walter Roberson 2022 年 1 月 13 日
Change
h = polarhistogram (deg2rad(x),deg2rad(y);
to
h = polarhistogram(deg2rad(x), deg2rad(y));

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