search character in table
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symbol ={'R0';'R1';'R2';'R3';'R4';'R5';'R6';'R7';'R8';'R9';'R10';'R11';'R12';'R13';'R14';'R15';'SCREEN';'KBD';'SP';'LCL';'ARG';'THIS';'THAT'};
Address={'0';'1';'2';'3';'4';'5';'6';'7';'8';'9';'10';'11';'12';'13';'14';'15';'16384';'24576';'0';'1';'2';'3';'4'};
symboltable=table(symbol,Address);
k6 = isfield(symboltable.symbol,trim_Ainstruction)
where 'trim_Ainstruction' is a char ..and we are assigning trim_Ainstruction as screen(in char data type)
while am trying to search 'screen' in table 'symboltable' using above code, its returns zero eventhough the specific string is in the table. can anyone help me?
0 件のコメント
回答 (1 件)
Cris LaPierre
2022 年 1 月 13 日
You are not using isfield correctly. This function is for searching structure array fieldnames, not character vectors.
symbol ={'R0';'R1';'R2';'R3';'R4';'R5';'R6';'R7';'R8';'R9';'R10';'R11';'R12';'R13';'R14';'R15';'SCREEN';'KBD';'SP';'LCL';'ARG';'THIS';'THAT'};
Address={'0';'1';'2';'3';'4';'5';'6';'7';'8';'9';'10';'11';'12';'13';'14';'15';'16384';'24576';'0';'1';'2';'3';'4'};
symboltable=table(symbol,Address);
ismember('R6',symboltable.symbol)
5 件のコメント
Cris LaPierre
2022 年 1 月 13 日
編集済み: Cris LaPierre
2022 年 1 月 13 日
Yes, logical results can be used for your if condition. That's new information that was not in the original question. What is the condition you want to have?
symbol ={'R0';'R1';'R2';'R3';'R4';'R5';'R6';'R7';'R8';'R9';'R10';'R11';'R12';'R13';'R14';'R15';'SCREEN';'KBD';'SP';'LCL';'ARG';'THIS';'THAT'};
Address={'0';'1';'2';'3';'4';'5';'6';'7';'8';'9';'10';'11';'12';'13';'14';'15';'16384';'24576';'0';'1';'2';'3';'4'};
symboltable=table(symbol,Address);
isfound = ismember('R6',symboltable.symbol);
if isfound
disp('Value found in symbol')
end
As you can see if the example above, the code you have provided here returns a single value. Share the code you are running.
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