Error in using eval statement
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Why it shows an incomplete statement ?
I'm trying to write this statement using eval as follows : Energy_H_A1S1 = rms (H_A1S1); but in eval it shows error ?
Thanks in advance.
eval(['Energy_H_A',num2str(1),'S',num2str(1),' = rms(H_A',num2str(1),'S',num2str(1);]);
2 件のコメント
Stephen23
2022 年 1 月 10 日
編集済み: Stephen23
2022 年 1 月 10 日
"I'm trying to write this statement using eval as follows : Energy_H_A1S1 = ..."
And that is the start of your problems.
Forcing meta-data into variable names makes acessing your data complex, slow, inefficient, and buggy... as your question demonstrates. Meta-data is data. Data should be stored in variables, not in variable names.
Your poor data design forces you into writing bad code, which could be easily avoided by storing the meta-data correctly.
採用された回答
Paul
2022 年 1 月 10 日
There's almost certainly a better way to organize the data and store the results, but if you must use eval:
['Energy_H_A',num2str(1),'S',num2str(1),' = rms(H_A',num2str(1),'S',num2str(1);]
should be:
['Energy_H_A',num2str(1),'S',num2str(1),' = rms(H_A',num2str(1),'S',num2str(1),');']
4 件のコメント
Paul
2022 年 1 月 10 日
Stephen23
2022 年 1 月 10 日
編集済み: Stephen23
2022 年 1 月 10 日
"Could you please also post an example of the mentioned better way instead of eval as it takes high running time for this varying A1..4..S1..4 data"
The MATLAB introductory tutorials also show how to use MATLAB effectively by using arrays and indexing:
その他の回答 (1 件)
Walter Roberson
2022 年 1 月 10 日
Asking how to use eval without problems is like asking how to use a chainsaw without its chain guard. It would be irresponsible for us to answer in any way other than "Don't do that!"
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