[y,Fs] = audioread('C:\Users\Casper\Desktop\3.3V.wav');
L=length(y); % series length
;
f = Fs/2*linspace(0,1,L/2+1); % single-sided positive frequency
X = fft(y)/L; % normalized fft
PSD=2*abs(X(1:L/2+1)); % one-sided amplitude spectrum
figure,plot(f,PSD);
grid
xlabel('freq(Hz)')
ylabel('amplitude')

 採用された回答

Star Strider
Star Strider 2021 年 12 月 28 日

1 投票

Try this —
idx = (f <= 1500) & (f <= 1800)
[rpm, freq] = findpeaks(PSD(idx), f(idx), 'MinPeakHeight',0.75E-3)
Without the data, I cannot experiment with that, however it should return the peak value as ‘rpm’ and the frequency as ‘freq’. If it does not, experiment with 'MinPeakProminence' instead of 'MinPeakHeight' since it cannot be determined from the plot that there are not more components to the desired peak.
.

2 件のコメント

burak Kalayoglu
burak Kalayoglu 2021 年 12 月 28 日
Thank you king
Star Strider
Star Strider 2021 年 12 月 28 日
As always, my pleasure!
.

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その他の回答 (1 件)

Voss
Voss 2021 年 12 月 28 日

0 投票

You could use Data Cursor to create a datatip, or you could try something like this:
idx = find(f(:) > 1000 & f(:) < 2500 & PSD(:) > 0.00075);

3 件のコメント

burak Kalayoglu
burak Kalayoglu 2021 年 12 月 28 日
編集済み: burak Kalayoglu 2021 年 12 月 28 日
I want to find a value1698 (signed point in graph) but ı cant , ı want to find signed point and after ı can find rpm this signal
Voss
Voss 2021 年 12 月 28 日
What does this do?
f(1698)
PSD(1698)
burak Kalayoglu
burak Kalayoglu 2021 年 12 月 28 日
Because I want to see what corresponds to the same psd value in different signals

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