Conditionally Flip Sign in Table
3 ビュー (過去 30 日間)
表示 古いコメント
I have a very simple question. Based on a matrix like this one:
A = [repmat({'Yes'},3,1) , repmat({'2'},3,1); repmat({'No'},3,1) , repmat({'2'},3,1)];
I want to flip the sign of column 2 if the entry in colum one is 'No', but leave it as is if the entry in colun one is 'Yes'.
The result should be the following:
B = [repmat({'Yes'},3,1) , repmat({'2'},3,1); repmat({'No'},3,1) , repmat({'-2'},3,1)];
I suppose I can do this using one line of code using cellfun, but I am not sure what is the most optimized way.
Thx for your help!
0 件のコメント
採用された回答
Matt Tearle
2014 年 11 月 4 日
編集済み: Matt Tearle
2014 年 11 月 4 日
One liner:
A(strcmp(A(:,1),'No'),2) = strcat('-',A(strcmp(A(:,1),'No'),2))
Slightly cleaner with two lines:
idx = strcmp(A(:,1),'No');
A(idx,2) = strcat('-',A(idx,2))
But... if you're worrying about efficiency, I'd want to know if A has to be in the form it is. Does the second column have to text, rather than numeric?
And do you have 13b or later (or Statistics TB)? Because I think you might have an easier time using tables and categoricals. For example:
% Make a table version of A
Atable = cell2table(A,'VariableNames',{'YesOrNo','Number'})
% Convert strings to categories and string numbers to actual numbers
Atable.YesOrNo = categorical(Atable.YesOrNo)
Atable.Number = str2double(Atable.Number)
% Now, do the sign flipping
Atable.Number(Atable.YesOrNo == 'No') = -Atable.Number(Atable.YesOrNo == 'No')
その他の回答 (0 件)
参考
カテゴリ
Find more on Tables in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!