Error using ~= Matrix dimensions must agree during using while function

1 回表示 (過去 30 日間)
jarvan
jarvan 2014 年 11 月 4 日
コメント済み: Walter Roberson 2017 年 10 月 7 日
I was testing the while loop for my ATM script.
password = 'jjteam'
password =
ucsdmate
balance = num1str(9.5405*100,'%10.2f%')
lastlogindate = datenum(2014,11,2,11,7,39)
lastlogindate =
7.3591e+05
datestr(lastlogindate)
rate = num2str(0.02*100,'%5.2f%%')
I save above code as atm.mat.
load ('atm.mat')
inpass = input('Enter your password : ','s');
while inpass ~= mypassword
disp('The passwoard is wrong,please try again.')
inpass = input('Enter your password : ','s');
end
fprintf('Your password is right.\n')
However, when I try to test my script, it said Error using ~= Matrix dimensions must agree. And Error in atm ,while inpass ~= mypassword. I am not sure which part I did wrong. Can anyone point it out? Thanks

採用された回答

Guillaume
Guillaume 2014 年 11 月 4 日
編集済み: Guillaume 2014 年 11 月 4 日
Use strcmp to compare strings. == and ~= will only work if the strings are the same length.
while ~strcmp(inpass, mypassword)
...
  3 件のコメント
Abdul Kazi
Abdul Kazi 2017 年 10 月 7 日
Hi, but what if I wanted it to work despite the strings not being same length?
Walter Roberson
Walter Roberson 2017 年 10 月 7 日
If you are using character vectors and you want to be able to use == to compare character vectors that might be different lengths, and you do not want to use strcmp, then you will need to create a new eq() method for the @char class and you will need to ensure that you version is earlier on the MATLAB path than the built-in version.
If you are using R2016b or later, you could use the string data type instead of character vectors, such as
string(inpass) ~= string(mypasswd)

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その他の回答 (1 件)

Julia
Julia 2014 年 11 月 4 日
Hi,
I don't see where you use "mypassword". You declare only the string "password".

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