not able to solve the integration function

1 回表示 (過去 30 日間)
Kundan Prasad
Kundan Prasad 2021 年 12 月 16 日
コメント済み: Kundan Prasad 2021 年 12 月 16 日
Dear Sir/Madam,
I am not able to solve the given integration function. The screenshot of given is attached and the code is given below
Thank you
for j=1:100
x(j)=linspace(0,0.025,101);
R(j)=linspace(0,0.4,101);
f=0.025;
syms x
b(j)= int(R(j)-sqrt(R(j).^2-x(j).^2),0, f);
c(j)=sqrt((1/f)*b(j));
end
  6 件のコメント
Kundan Prasad
Kundan Prasad 2021 年 12 月 16 日
yes sir
for given R=0.4, f=0 & 0.025, x=0:0.001:0.025,
what will be the value of σ for each x
Kundan Prasad
Kundan Prasad 2021 年 12 月 16 日
here f=0.025

サインインしてコメントする。

回答 (2 件)

Jan
Jan 2021 年 12 月 16 日
This cannot work:
x(j) = linspace(0,0.025,101);
On the left is a scalar and on the right a vector with 101 elements.
Seeing only the invalid code does not clarify its intention. What is the purpose of the loop?
  2 件のコメント
Kundan Prasad
Kundan Prasad 2021 年 12 月 16 日
what need to be change in code. Please clarify??
Thank you
Jan
Jan 2021 年 12 月 16 日
I cannot fix the code such that it does, what you want, as long as you do not clarify what you want to achieve. I ask again: What is the purpose of the loop? I'd expect RT to be a constand and x to be a symbolic variable. Then there is no need for a loop.

サインインしてコメントする。


Tesfaye Girma
Tesfaye Girma 2021 年 12 月 16 日
indeces should have to match in both side and be compatable as well

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by