not able to solve the integration function
古いコメントを表示
Dear Sir/Madam,
I am not able to solve the given integration function. The screenshot of given is attached and the code is given below
Thank you

for j=1:100
x(j)=linspace(0,0.025,101);
R(j)=linspace(0,0.4,101);
f=0.025;
syms x
b(j)= int(R(j)-sqrt(R(j).^2-x(j).^2),0, f);
c(j)=sqrt((1/f)*b(j));
end
6 件のコメント
Kundan Prasad
2021 年 12 月 16 日
Walter Roberson
2021 年 12 月 16 日
Solve for what value?
Is σ a constant?
Is the task to solve for f for each of a list of R values ?
Your vectors are length 101; why do you only loop to 100 ?
Kundan Prasad
2021 年 12 月 16 日
What is being solved for?
Is the question how to calculate the right hand side given R, f, and symbolic x, outputting sigma ?
Normally when the phrase "integral equation" is used, it means that some variable inside an integral or some bound of the integral needs to be modified to find the correct value to match the other side of the equation. For example,
syms x b
solb = vpasolve(int(cos(x)^2 + tan(x/10), x, 0, b) == 1)
Kundan Prasad
2021 年 12 月 16 日
Kundan Prasad
2021 年 12 月 16 日
回答 (2 件)
Jan
2021 年 12 月 16 日
This cannot work:
x(j) = linspace(0,0.025,101);
On the left is a scalar and on the right a vector with 101 elements.
Seeing only the invalid code does not clarify its intention. What is the purpose of the loop?
2 件のコメント
Kundan Prasad
2021 年 12 月 16 日
Jan
2021 年 12 月 16 日
I cannot fix the code such that it does, what you want, as long as you do not clarify what you want to achieve. I ask again: What is the purpose of the loop? I'd expect RT to be a constand and x to be a symbolic variable. Then there is no need for a loop.
Tesfaye Girma
2021 年 12 月 16 日
0 投票
indeces should have to match in both side and be compatable as well
カテゴリ
ヘルプ センター および File Exchange で Code Performance についてさらに検索
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!