count repeated sequence in an array

data=[0 0 0 1 1 0 0 0 0 0 0 1 1 1 1]

L = length(data)

result0 = sum (data == 0)

result1 = sum (data == 1)

ctr1 = 0;

ctr2 = 0;

for i= 1:length(data)

if data(i) == 0

ctr1 = ctr1 + 1

elseif data(i) == 1

ctr2 = ctr2 + 1

end

end

str = [ctr1 ctr2]

end

I'm struck here

I'm expecting the output as [3 4 2 6] and separate the output as low [3 6] and high [2 4]

Please use only basic commands (use only loop)

no runlength and other complicated commands

Answer 1

[Awais Saeed]

Not so neat, but will do the work

data=[0 0 0 1 1 0 0 0 0 0 0 1 1 1 1];
zero_count = 0;
one_count = 0;
ctr1 = [];
ctr0 = [];
% loop through data
for col = 1:1:size(data,2)
    % if its a 0, do the following
    if(data(col) == 0)
        zero_count = zero_count + 1;
        % check for index out of bound
        if(col+1 <= size(data,2))
            % if next element is 1, stop incrementing zero_count
            if(data(col+1) == 1)
                ctr0 = [ctr0 zero_count]
                zero_count = 0;     % reset count
            end
        else
            % if index is out of bound, inspect last element
            if(data(end) == 0), ctr0 = [ctr0 zero_count],end
            if(data(end) == 1), one_count = one_count + 1; ctr1 = [ctr1 one_count],end
        end
    else
        % if its a 1, do the following
        one_count = one_count + 1;
        if(col+1 <= size(data,2))
            if(data(col+1) == 0)
                ctr1 = [ctr1 one_count]
                one_count = 0;     % reset count
            end
        else
            if(data(end) == 0), zero_count = zero_count+1; ctr0 = [ctr0 zero_count],end
            if(data(end) == 1), ctr1 = [ctr1 one_count],end
        end
    end
end

ctr0 = 3

ctr1 = 2

ctr0 = 1×2

3 6

ctr1 = 1×2

2 4