itr=0; % number of iteration
for t=1:1:3
itr=itr+1;
b(itr)=[sin(t) cos(t)];
end
In the above code , I am getting the error " Unable to perform assignment because the indices on the left side are not compatible with the size of the right side."
Please tell me how to fix.

 採用された回答

Chunru
Chunru 2021 年 12 月 11 日

0 投票

itr=0; % number of iteration
for t=1:1:3
itr=itr+1;
b(itr, :)=[sin(t) cos(t)]; % Two numbers for each iteration form a row for a matrix b (nitr x 2)
end
b
b = 3×2
0.8415 0.5403 0.9093 -0.4161 0.1411 -0.9900

4 件のコメント

SANDIPKUMAR ROYADHIKARI
SANDIPKUMAR ROYADHIKARI 2021 年 12 月 11 日
Thank you
SANDIPKUMAR ROYADHIKARI
SANDIPKUMAR ROYADHIKARI 2021 年 12 月 12 日
itr=0; % number of iteration
for t=1:1:3
itr=itr+1;
b(itr, :)=[sin(t) cos(t)];
c(itr, :)=[1-sin(t) 1];
d(itr,:)=[b;c];
end
I get this error------Unable to perform assignment because the indices on the left side are not compatible with the size of the right side.
Please help
Chunru
Chunru 2021 年 12 月 12 日
itr=0; % number of iteration
for t=1:1:3
itr=itr+1;
b(itr, :)=[sin(t) cos(t)];
c(itr, :)=[1-sin(t) 1];
end
d=[b c]
d = 3×4
0.8415 0.5403 0.1585 1.0000 0.9093 -0.4161 0.0907 1.0000 0.1411 -0.9900 0.8589 1.0000
Walter Roberson
Walter Roberson 2021 年 12 月 12 日

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