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Mean of Multiple data sets across a time series

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FIONA HOTCHKISS
FIONA HOTCHKISS 2021 年 12 月 8 日
回答済み: Aman 2024 年 4 月 18 日
I have 5 sets of CO2 concentrations, all taken at different locations. They have different start dates, the earliest beginning in 1957 and the latest in 1981 all up until the present. I would like to find the average of all 5 locations to create one line and be able to plot it against time, I believe this would take a for loop which I am not very experienced in. I also considered keeping the datasets separate and just finding the averages of each and using hold on to plot them against each other, but I again run into the issue of figuring out how to code to loop to keep it against time. If one of these ways would be a better option for how I should analyze my data that would be helpful.
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FIONA HOTCHKISS
FIONA HOTCHKISS 2021 年 12 月 8 日
My data came in a .csv file, would I be able to share it to you through that? Or should I share my entire livescript to you? I tried uploading a file here and it was not working for me so I am unsure if I am doing that correctly.
Voss
Voss 2021 年 12 月 9 日
Yeah, if you can upload the .csv file, that would be perfect.
If you're unable to do so, maybe it's too large? Probably just the top however many rows would be sufficient for me to get an idea of what the data is. If all else fails, maybe a screen shot of the .csv open in Excel or whatever would work well enough.

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Aman
Aman 2024 年 4 月 18 日
Hi Fiona,
As per my understanding, you want to get the mean CO2 where the reading has been taken at different locations and the time stamp of the recording is also different.
Without the actual data, it is difficult to tell the solution upfront, but I have created a sample example code where I have created a table that contains readings in ppm across different locations and were taken at different months. Now, in order to calculate the mean, I'm getting the reading across the same month and then calculating the mean. You can refer to the below code for your reference.
location = ["A";"A";"B";"B";"B";"C";"C";"D"];
month = ["Jan";"Mar";"Jan";"Feb";"Mar";"Feb";"Mar";"Jan"];
ppm = [10;20;30;40;50;60;70;80];
dataTable = table(location,month,ppm);
dataArray = table2array(dataTable);
uniqueMonths = unique(dataArray(:,2));
for i=1:length(uniqueMonths)
requiredPPM = dataArray(dataArray(:,2)==uniqueMonths(i),3);
monthMean = mean(str2double(requiredPPM));
disp("Mean of " + uniqueMonths(i) + " is " + monthMean);
end
Mean of Feb is 50 Mean of Jan is 40 Mean of Mar is 46.6667
Hope it helps!

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