here is the question :
function can return a vector as a result. Write a function vecout that will receive
one integer argument and will return a vector that increments from the value of
the input argument to its value plus 5, using the colon operator.
I got : function vector= vecout(integer)
start= integer;
end= integer + 5;
vector= start:end;
end
The answer display Empty matrix: 1-by-0 What should I fix this porblem

 採用された回答

Mohammad Abouali
Mohammad Abouali 2014 年 10 月 26 日
編集済み: Mohammad Abouali 2014 年 10 月 26 日

1 投票

This is very tricky
You can not use end as a variable name. That is a reserved word.
SO pretty much your definition of the function:
function vector= vecout(integer)
start= integer;
end = integer + 5;
vector= start:end;
end
becomes:
function vector= vecout(integer)
start= integer;
end
everything after the first "end" is ignored so vector is never assigned anything; thus returning as an empty array.
Correct it this way
function vector=vecout(n)
vector=n:n+5;
end

4 件のコメント

david Chan
david Chan 2014 年 10 月 26 日
i can do this with + but cannot do this in - like function vector=vecout(n) vector=n:n-5; end
it still said Empty matrix: 1-by-0
Mohammad Abouali
Mohammad Abouali 2014 年 10 月 26 日
編集済み: Mohammad Abouali 2014 年 10 月 26 日
n:n-5 returns a null vector.
Because n-5 is definitely smaller than n so that generates nothing. If you want it to generate something it should be n:-1:n-5. Then it starts going down (-1 step) to reach n-5. With plus n:+1:n+5 but since +1 is the default step you can omit it and just type n:n+5. That's why one works and the other doesn't.
david Chan
david Chan 2014 年 10 月 26 日
I get it thank you for your answer
Mohammad Abouali
Mohammad Abouali 2014 年 10 月 26 日
You are welcome

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