The attachment is here. Thank you.
How to plot multiple output responses of transfer functions in the same figure?
26 ビュー (過去 30 日間)
古いコメントを表示
How can I plot this state space like the graph I attached by using tf() and step() command? Thank you!

採用された回答
Yusuf Suer Erdem
2021 年 11 月 29 日
編集済み: Yusuf Suer Erdem
2021 年 11 月 29 日
Try these codes below please;
clc; clear; close all;
numerator = 1;
denominator = [1,1,3,1];
sys = tf(numerator,denominator);
yyaxis left
plot(step(sys));
yyaxis right
plot(impulse(sys));
その他の回答 (2 件)
Anish Mitra
2025 年 11 月 14 日
移動済み: Sam Chak
2025 年 11 月 14 日
If the use of yyaxis is not needed, then the stepplot command can be directly used to generate the step response. Beginning in R2024b, the chart object created has a set of properties that can be modified to customize the style.
numerator = 1;
denominator = [1,1,3,1];
sys = tf(numerator,denominator);
figure(1)
sp = stepplot(sys);
Responses can be added by using hold on or the addResponse function.
denominator2 = [1 1 4 1];
sys2 = tf(numerator,denominator2);
hold on;
stepplot(sys2);
legend('sys1', 'sys2')
or
% denominator2 = [1 1 4 1];
% sys2 = tf(numerator,denominator2);
figure(2)
sp = stepplot(sys);
addResponse(sp,sys2);
legend('sys1', 'sys2')
See list of all linear analysis plots.
0 件のコメント
Adem
2024 年 2 月 7 日
clc; clear; close all;
numerator = 1;
denominator = [1,1,3,1];
sys = tf(numerator,denominator);
yyaxis left
plot(step(sys));
yyaxis right
plot(impulse(sys));
0 件のコメント
参考
カテゴリ
Help Center および File Exchange で Linear Model Identification についてさらに検索
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
