How to plot multiple output responses of transfer functions in the same figure?

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Ali Deniz
Ali Deniz 2021 年 11 月 29 日
移動済み: Sam Chak 2025 年 11 月 14 日
How can I plot this state space like the graph I attached by using tf() and step() command? Thank you!

採用された回答

Yusuf Suer Erdem
Yusuf Suer Erdem 2021 年 11 月 29 日
編集済み: Yusuf Suer Erdem 2021 年 11 月 29 日
Try these codes below please;
clc; clear; close all;
numerator = 1;
denominator = [1,1,3,1];
sys = tf(numerator,denominator);
yyaxis left
plot(step(sys));
yyaxis right
plot(impulse(sys));

その他の回答 (2 件)

Anish Mitra
Anish Mitra 2025 年 11 月 14 日
移動済み: Sam Chak 2025 年 11 月 14 日
If the use of yyaxis is not needed, then the stepplot command can be directly used to generate the step response. Beginning in R2024b, the chart object created has a set of properties that can be modified to customize the style.
numerator = 1;
denominator = [1,1,3,1];
sys = tf(numerator,denominator);
figure(1)
sp = stepplot(sys);
Responses can be added by using hold on or the addResponse function.
denominator2 = [1 1 4 1];
sys2 = tf(numerator,denominator2);
hold on;
stepplot(sys2);
legend('sys1', 'sys2')
or
% denominator2 = [1 1 4 1];
% sys2 = tf(numerator,denominator2);
figure(2)
sp = stepplot(sys);
addResponse(sp,sys2);
legend('sys1', 'sys2')
See list of all linear analysis plots.

Adem
Adem 2024 年 2 月 7 日
clc; clear; close all;
numerator = 1;
denominator = [1,1,3,1];
sys = tf(numerator,denominator);
yyaxis left
plot(step(sys));
yyaxis right
plot(impulse(sys));

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