matching the element of matrix with an array

Suppose i have an array as,

A={ [2,3;2,7] [3,2;3,4;3,8] [4,3;4,5] [5,4;5,10] [7,2;7,8;7,12] }

and a matrix as B=[17,8,14,4,18]

now i want to match the element from B with A and want answer as

C={ [ ] [3,4 ; 3,8] [4] [5,4] [7,8] }

plz help

[Jan]

Please explain the relation between A, B and C. What does "match" mean here?

[Mausmi Verma]

A is an cell array representing some routes, and B is a matrix representing the node may or may not exist in the routes. So if any node from B exists in the any of the routes given in A, then that route will be available and if not then that route doesnt exists and the final answer should be in the way given in C. I may not be good in framing my question in a proper way, so i apologise for that

[Jan]

A general hint: The cell array contains matrices, which consist of numbers. Explain problem in the terms Matlab can work with. "routes" and "nodes" are the meaning of the numbers, but this does not matter for Matlab, so it does not for solving the problem.

There is no need for apologies: It is a standard step in solving a problem to ask questions for clarifications. Your question about Matlab are welcome here.

Answer 1

[Jan]

A = {[2,3;2,7], [3,2;3,4;3,8], [4,3;4,5], [5,4;5,10], [7,2;7,8;7,12]};
B = [17,8,14,4,18]

B = 1×5

17 8 14 4 18

C = cell(size(A));
for iA = 1:numel(A)
    a     = A{iA};
    match = any(ismember(a, B), 2);
    if any(match)
       C{iA} = a(match, :);
    end
end
celldisp(C)

 
C{1} =
 
     []
 
 
C{2} =
 
     3     4
     3     8

 
 
C{3} =
 
     4     3
     4     5

 
 
C{4} =
 
     5     4

 
 
C{5} =
 
     7     8

 

% C={ [ ]  [3,4 ; 3,8] [4] [5,4] [7,8] }

[Mausmi Verma]

Thank a lot.....your answer is of so much help for me