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How do I input a matrix (variable) in a function?

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hithere
hithere 2014 年 10 月 22 日
コメント済み: hithere 2014 年 10 月 22 日
I created a function:
.
x is the excitation wavelength where i will input eg. " test,wavelength(765,y)"
.
y is a 729 by 1 matrix: .
.
the result is:
.
.
where only the first number of y matrix is being implemented in the function. How do i create a function where the first number of y matrix will be implemented and return as a result as the first number in wavelengtha matrix and so on.
  1 件のコメント
the cyclist
the cyclist 2014 年 10 月 22 日
The screenshots are very helpful in understanding your problem. I suggest not using them for the actual code, though, so that we can copy & paste your code into MATLAB ourselves.

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採用された回答

Mohammad Abouali
Mohammad Abouali 2014 年 10 月 22 日
1) why you have comma in your function name?
2) Change your equation in element wise division as follow:
wavelengtha= 1./ ((1./x)-(y/10^7))
  3 件のコメント
Mohammad Abouali
Mohammad Abouali 2014 年 10 月 22 日
One way is to do this:
let's say x=[765, 766, 777]
then you can do this:
for i=1:numel(x) wavelengtha{i}= yourFunction(x(i), ...) end
I still don't get the comma in your function name?
hithere
hithere 2014 年 10 月 22 日
sorry i have rename my function to just
.
function [wavelengtha] = test(x,y)
wavelengtha = 1./ ((1./x)-(y/10^7));
for i=1:numel(x)
wavelengtha{i}= test(x(i), ...);
end
end
. However i cant get the for loop to work.

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その他の回答 (1 件)

the cyclist
the cyclist 2014 年 10 月 22 日
I'm not sure I fully understand what you mean, but does this do what you intend?
wavelengtha = 1./((1./x) - (y/10^7));
Notice that I used element-wise division.
  1 件のコメント
hithere
hithere 2014 年 10 月 22 日
Thank you for you help!
As far as i understand. the result will return as a new variable in my workspace. Even when i change the input of x. The resulted variable will replace my previous work. is there a way to have the resulting variable number somewhat related to my input x eg(x = 765. then the wavelengtha out automatically output as wavelengtha765 something like that)

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