How to make a bar graph out of the first and second column of a matrix?

I have matrix

sleeprxn2= [ 0 0.6229

1.0000 0.3404

1.0000 0.2744 ]

I would like if sleeprxn2 is equal to 0, then plot on bar graph 0.6299, and if sleeprxn2 is equal to 1, then plot the mean of the numbers (0.3404 and 0.2744). I would like this to be applied to many more numbers in the future.. I've tried what you see below.

I feel like it shouldn't be this difficult.

rRbar = [0.6229 0.3404 0.2744]

sleep_vec = [0,1,1]

% plot of reaction times to hours sleep   
figure
    subplot(1,2,1)
    bar(sleep_vec,rRbar,'r')
    hold on;
    subplot(1,2,2)
    bar(sleep_vec,rBbar,'b')
       % needs worked


%%%%%%
morethan=0
lessthan=0
more8=[];
less8=[];
for i=1:length(sleep_vec)
    if sleep_vec >= 1
        morethan=morethan+1
    else
        sleep_vec < 1
        lessthan=lessthan+1
    end
    more8=[more8 morethan];
    less8=[less8 lessthan];
end
subplot(1,2,1);
bar(more8,rR,'r');
hold on
subplot(1,2,2);
bar(less8,rB,'b');


%%%%%
for i=1:length(sleep_vec)
    if sleep_vec == 1
        plot(sleep_vec,'ro')
    else
        sleep_vec == 0
        plot(sleep_vec,'bo')
    end
end

%%%%%%red reaction time to sleep
sleeprxn=[sleep_vec rRbar]
sleeprxn2=reshape(sleeprxn,3,[])

for i=1:length(sleep_vec)
    if sleeprxn2 == 1
        plot(sleeprxn2(:,2));
    else sleeprxn2 == 0
        plot(sleeprxn2(:,2));
    end
end

s=sleeprxn2
x=s(:,1);
y=s(:,2);
bar(x,y)



       
    greater=numel(find(sleep_vec==1));
    bar(greater,rRbar,'r');
    hold on
    less=numel(find(sleep_vec==0));
    bar(less,rRbar,'g');
end

sleeprxn=[sleep_vec rRbar]
sleeprxn2=reshape(sleeprxn,3,[])

    rR=reshape(reactionTime_red_vec,2,[])

Answer 1

[Adam Danz]

sleeprxn2= [         0    0.6229
                    1.0000    0.3404
                    1.0000    0.2744 ]

sleeprxn2 = 3×2

0 0.6229 1.0000 0.3404 1.0000 0.2744

[groups, groupID] = findgroups(sleeprxn2(:,1)); 
groupMeans = splitapply(@mean, sleeprxn2(:,2), groups);
bar(groupID, groupMeans)

[Kristin Aldridge]

Thank you so much!