Input argument for ode45 function type error

1 回表示 (過去 30 日間)
Aleem Andrew
Aleem Andrew 2021 年 11 月 7 日
コメント済み: Star Strider 2021 年 11 月 7 日
I am trying to modify the following code.
tspan = [0 10];
x0 = 0;
[t,x] = ode45(@(t,x) (-4.76e+1*x^2 + 5.69e-9*x + 7.98e-2)/(1.67e+4*x + 1.12), tspan, x0);
plot(t,x,'b')
xlim([0 0.001])
The input argument to the ode45 function is directly typed in. If instead you write it as
tspan = [0 10];
x0 = 0;
f = (-4.76e+1*x^2 + 5.69e-9*x + 7.98e-2)/(1.67e+4*x + 1.12);
[t,x] = ode45(@(t,x) f, tspan, x0);
plot(t,x,'b')
xlim([0 0.001])
then there is an error, even though the type of the argument is the same. Can anyone explain how the argument can be input as a variable that stores the expression?

採用された回答

Star Strider
Star Strider 2021 年 11 月 7 日
Yes.
Create it as an anonymous function at the outset —
tspan = [0 10];
x0 = 0;
f = @(t,x) (-4.76e+1*x^2 + 5.69e-9*x + 7.98e-2)/(1.67e+4*x + 1.12);
[t,x] = ode45(f, tspan, x0);
figure
plot(t,x,'b')
grid
xlim([0 0.001])
.
  4 件のコメント
Aleem Andrew
Aleem Andrew 2021 年 11 月 7 日
Thank you, I appreciate your help
Star Strider
Star Strider 2021 年 11 月 7 日
As always, my pleasure!
.

サインインしてコメントする。

その他の回答 (0 件)

カテゴリ

Help Center および File ExchangeSymbolic Math Toolbox についてさらに検索

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by