how to rotate integer vector from right to left and vis versa

Write afunction called rotleft that will receiveone row vector as an argument (you mayassume that it is a row vector with a length of at least two) and willreturn another vector, whichconsists of the input vector rotatedto the left—e.g., all values shift over one element, and the first element iswrapped around to theend. For example,

>> rotleft([1 3 4]) ans =

3 4 1

could anyone help please ?

[TADA]

Since this is an hw task, i will give you some breadcrumbs. This is a vector indexing problem.

The easiest solution requires you to generate the correct index.

this post on matrix indexing should give you a good idea of where to start

https://www.mathworks.com/company/newsletters/articles/matrix-indexing-in-matlab.html

[Abdullah Sultan]

Dear TADA, thank you for your concern, actually it's not hm, I have finished the Matlab subject in last year . Actually, now I train myself. I make a revision to apply for the MATHWORK official exam. Thank you again

[Abdullah Sultan]

checkout this and give me your opinion

function Rotatvec = vecRot(vec)

% this function is to rotate vector

% the maximum number mudt user enter is 18

vec= input('enter your max number from 1 to 18:')

vecRot= [20:-1:vec]

end

Answer 1

[DGM]

Something like this

shamount = 1; % amount to shift left (negative to shift right)

A = 1:5 % test vector

A = 1×5

1 2 3 4 5

B = circshift(A,[0 -shamount]) % using circshift

B = 1×5

2 3 4 5 1

C = A(mod((1:numel(A))+shamount-1,numel(A))+1) % using basic indexing

C = 1×5

2 3 4 5 1

[Abdullah Sultan]

thank you for your help

i'd like to present my work and give me your opinoin

function Rotatvec = vecRot(vec)

% this function is to rotate vector

% the maximum number mudt user enter is 18

vec= input('enter your max number from 1 to 18:')

vecRot= [20:-1:vec]

end

[DGM]

Pass parameters as input arguments instead of pestering the user for interactive inputs.

The result is assigned to a variable with the same name as the function instead of the output argument.

The rotation method doesn't do what you think it does. Consider:

vec = [12 15 20 17]

vec = 1×4

12 15 20 17

B = [20:-1:vec] % just creates a linear vector from 20 to vec(1)

B = 1×9

20 19 18 17 16 15 14 13 12

I already mentioned ways to do this.

myvecrot(1:10,2)

ans = 1×10

3 4 5 6 7 8 9 10 1 2

myvecrot(1:10,-2)

ans = 1×10

9 10 1 2 3 4 5 6 7 8

function outvec = myvecrot(invec,k)
    outvec = invec(mod((1:numel(invec))+k-1,numel(invec))+1);
end