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who can create a surf y=0 in a defined domain?
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hi friends
i want to create a surf y=0 in a domain by surf and linspace functions with this code:
hsp = surf(linspace(-0.3,1.3,200),zeros(200)+0.125,linspace(-0.251776695,0.501776695,200));
but it errors.
for the case z=0 the following code is correct:
hsp = surf(linspace(-0.3,1.3,200),linspace(-0.251776695,0.501776695,200),zeros(200)+0.125);
but for y=0 it errors:
Z must be a matrix, not a scalar or vector.
help me if you can.
thanks a lot
2 件のコメント
Stephen23
2014 年 10 月 3 日
Please stop double posting (or in your case, triple posting).
If you wish to make people aware of your question, you only need to add a comment to the original question and it come to the front of the list.
Imagine other readers here: we don't know what advice you already have become on the other posts of the same question, and we are not paid to find all three posts of your identical question, compare the current best answers and see if we can add anything better.
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Mike Garrity
2014 年 10 月 3 日
The 3rd arg to surf needs to be 2D. That's optional for the other two. You can use meshgrid to expand your 1D arrays out to 2D like this:
[x,z]=meshgrid(linspace(-0.3,1.3,200),linspace(-0.251776695,0.501776695,200));
surf(x,zeros(200)+.125,z)
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