13x8 Matrix Cubic Interpolation
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I have a matrix [13x8]. I want to cubic interpolate it to [50x8]. I tried "csapi" but I couldn't manage to figure it out.
[0.0000 0.0000 0.0000 0.0000 0.0000 0.0890 0.2860 0.4380;
0.0177 0.0648 0.0888 0.1070 0.1640 0.3680 0.5720 0.7040;
0.0594 0.1778 0.2445 0.3140 0.4250 0.6140 0.7650 0.8540;
0.2652 0.4723 0.6038 0.7260 0.8250 0.8970 0.9500 0.9820;
0.5436 0.7547 0.8852 0.9570 0.9800 0.9910 0.9980 1.0000;
0.7409 0.9056 0.9870 1.0000 1.0000 1.0000 1.0000 1.0000
0.7710 0.9260 0.9980 1.0000 1.0000 1.0000 1.0000 1.0000
0.7695 0.9260 0.9980 1.0000 1.0000 1.0000 1.0000 1.0000
0.6399 0.8297 0.9401 0.9710 0.9800 0.9850 0.9900 0.9920
0.3369 0.5788 0.7226 0.7780 0.8020 0.8270 0.8510 0.8770
0.0771 0.2463 0.3493 0.3890 0.4070 0.4300 0.4720 0.5360
0.0200 0.1019 0.1577 0.1770 0.1840 0.1940 0.2290 0.2990
0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0200 0.0510];
採用された回答
その他の回答 (2 件)
Image Analyst
2021 年 10 月 26 日
You can use imresize() to do bicubic interpolation, if you have the image Processing Toolbox
resizedMatrix = imresize(m, [50,8])
John D'Errico
2021 年 10 月 26 日
編集済み: John D'Errico
2021 年 10 月 26 日
1 投票
Simplest is to just read the help for interp2. It is silly to use a lower level tool when a high level tool does exactly what you want.
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