Here is my code sample:
t=[0,4,8,12,16,20];
y=[0.7,0.9,0.9,0.7,0.3,0];
for i=1:length(t)
u=[t(i) t(i+1) t(i+2)];
v=[y(i) y(i+1) y(i+2)];
i=i+3;
end

 採用された回答

Image Analyst
Image Analyst 2021 年 10 月 24 日

0 投票

Yes, you get new u and v vectors every time - is that what you mean by successive? By the way you should do it this way:
t = [0,4,8,12,16,20]
y = [0.7,0.9,0.9,0.7,0.3,0]
for k = 1 : 3 : length(t)-2
% Get a new u and v for this iteration:
u = t(k : k+2);
v = y(k : k+2);
% Now do something with u and v....
end

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