Matlab editor: the function might be unused

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Deerlin
Deerlin 2014 年 10 月 1 日
コメント済み: Mustafa Akgül 2020 年 12 月 9 日
Below is the body of my code.It keeps saying that func2 might be unused.I'm not sure how to fix this...
  3 件のコメント
Mustafa Akgül
Mustafa Akgül 2020 年 12 月 9 日
How can I define

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採用された回答

Julia
Julia 2014 年 10 月 1 日
編集済み: Julia 2014 年 10 月 1 日
Hi,
the easiest way is to make two files: one for func1 and one for func2. (I don't know if you can fix this problem using only one file.) In the file for func2 you have to add the Global-definition for G.
The file names must be the same as the function names.
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Julia
Julia 2014 年 10 月 1 日
So you don't have to implement those functions, you have to understand how global variables work.
It is really not complicated:
func1 can manipulate the global variable G since G is defined as global in this function. Whereas in func2 G is only a local variable.
Post your guesses for a, b, and G here and we will be able to tell you if you understood the concept right.

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その他の回答 (1 件)

Image Analyst
Image Analyst 2014 年 10 月 1 日
func2 was never used, never called, in func1. You just assigned y to some equation, which happened to be similar (but not the same) equation as in func2. You never said
y=fun2(x)
anywhere in your main function, func1.
You also need the line
global G;
inside func2 if func2 is to use the same value of G that func1 had. If you do that, and have the G=50 line, then it will also become 50 once you get back inside func1.
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Image Analyst
Image Analyst 2014 年 10 月 2 日
If it's not global, then she must pass it in via the input argument list. That's perhaps the best way. Other ways of getting the same G inside func2() (if you need the same G in there) are discussed in the FAQ http://matlab.wikia.com/wiki/FAQ#How_can_I_share_data_between_callback_functions_in_my_GUI.28s.29.3F. Of course maybe they don't want that and want you to see how the G in func2() is not the same value as the one in func1().
The homework problem instructions pass in G as part of an expression which is evaluated so it's not really passed in. Even if it were, it's overwritten with a value of 50, but since it's not global and not passed out, the 50 value won't be seen outside of func2().

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