replace values of x matrix for positions of y matrix where y=1

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Michal Sleszynski
Michal Sleszynski 2021 年 10 月 19 日
コメント済み: Michal Sleszynski 2021 年 10 月 19 日
I have a matrix x that is 12x12double and i have a matrix y also 12x12double.
Its important to note that im running a loop and i will later need to generate bigger sized matrices so i need a code that will work for them as well.
but for now each column of x has these values
col.1
  1. 3
  2. 2.85
  3. 2.55
  4. 2.25
  5. 1.95
  6. 1.65
  7. 1.35
  8. 1.05
  9. 0.75
  10. 0.45
  11. 0.15
  12. 0
y is this
1 1 1 1 1 1 1 1 1 1 1 1
0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 1 0 0 0 0 0 0
0 0 0 0 1 1 1 0 0 0 0 0
0 0 0 0 0 1 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0
1 1 1 1 1 1 1 1 1 1 1 1
i need the values of x to be equal to 1.5 for the positions of y where y = 1. how can i achieve this.

回答 (1 件)

Johannes Hougaard
Johannes Hougaard 2021 年 10 月 19 日
y = rand(33,33); % This is a y of random numbers between 0 and 1
x = round(rand(33,33)*0.7); % This is another x of random numbers between - rounded to either 1 or 0 as your y
y(x==1) = 1.5; % Assigns all y-values to 1.5 when x equals 1
  1 件のコメント
Michal Sleszynski
Michal Sleszynski 2021 年 10 月 19 日
Thank you seems like i was overthinking it

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