Taylor series using For loop to approximate Sin(x).
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function y = SIN(x)
%SIN This function takes the value and processes the approximate sin
%value of that input
% The value of sin is approximately calculated using Taylor Series
% from the input value x.
Sum = 0;
T = 1E-12; %defining tolerance.
for n = 0:29
an = ((-1)^n)*((x^((2*n)+1))/factorial((2*n)+1));
Sum = Sum + an;
if abs(an) < T || n==29
break
elseif abs(an) == T
disp 'More Iterations are needed to reach the specified tolerance.';
end
end
y = Sum;
end
the answer i am getting for lets say SIN(-3) = 4.500
however, the expected answer from using the built-in function sin(-3) = -0.1411.
how can i get the expected answer? I am very confused. THIS HAS TO BE DONE USING FOR LOOPS. How can i fix this code?
採用された回答
SIN(-3)
function y = SIN(x)
%UNTITLED Summary of this function goes here
% Detailed explanation goes here
n = 0; Sum = 0; an=1;
T = 1E-12; %defining tolerance.
for n = 0:30
an = ((-1)^n)*((x^((2*n)+1))/factorial((2*n)+1));
Sum = Sum + an;
if abs(an) < T || n==30
break
else
disp 'More Iterations are needed to reach the specified tolerance.'
end
end
y = Sum;
end
You had the wrong starting point for n, and you had the wrong test for breaking.
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