How to plot a function with 3 independent variables
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f(x,y,z)=0.95*x+0.73*y+0.62*z-130.05
f(x,y,z); x; y; and z are values between 0 and 100.
f(x,y,z) is shown in color. How can I plot in MATLAB similar to figure below.
Thank you!
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KSSV
2021 年 10 月 13 日
f = @(x,y,z) 0.95*x+0.73*y+0.62*z-130.05 ;
x = linspace(0,100) ;
y = linspace(0,100) ;
z = linspace(0,100) ;
[X,Y,Z] = meshgrid(x,y,z) ;
V = f(X,Y,Z) ;
isosurface(X,Y,Z,V,1e-4)
6 件のコメント
Walter Roberson
2021 年 10 月 14 日
f = @(x,y,z) 0.95*x+0.73*y+0.62*z-130.05 ;
x = linspace(60,100) ;
y = linspace(60,100) ;
z = linspace(60,100) ;
[X,Y,Z] = meshgrid(x,y,z) ;
V = f(X,Y,Z) ;
Vmin = min(V(:))
Vmax = max(V(:))
levels = 70:5:100;
Nlevels = length(levels);
cmap = hot(Nlevels);
for K = 1 : Nlevels
s = isosurface(X, Y, Z, V, levels(K));
p(K) = patch(s);
p(K).EdgeColor = 'none';
p(K).FaceColor = cmap(K,:);
isonormals(X, Y, Z, V, p(K));
end
camlight;
lighting gouraud;
xlim auto; ylim auto; zlim auto
view(3); view(36, 64);
legend(p, string(levels))
You cannot do contour lines because you are dealing with a 3D object: you can only do ISO surfaces.
It might be possible to get the colors right without some of the above steps. With the default steps I showed in https://www.mathworks.com/matlabcentral/answers/1562461-how-to-plot-a-function-with-3-independent-variables#comment_1783116 you might notice that the colors come out wrong compared to the legend: it turns out that you are looking at the "back" of the plates, and that you need to view() to see the front (or you need to move the light.)
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