display result
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I have a matrix "TRPfeat".
It conisits values of
>>TRPfeat
TRPfeat =
1.0e+003 *
0.0398 2.4990 0.0044 0.0010 0.0493
0.1015 2.4910 0.0033 0.0010 0.1826
0.1038 1.5180 0.0036 0.0010 0.1250
0.0733 0.8220 0.0024 0.0010 0.1180
0.0806 0.7420 0.0036 0.0010 0.1260
0.0465 0.7490 0.0033 0.0010 0.0789
0.0295 2.4040 0.0040 0.0010 0.0446
0.0193 2.4990 0.0037 0.0010 0.0254
My problem is, I dont want to use display multiple of 1.0e+003. Simply I need result with precision 6 digits after the decimal point.
How to do this?
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回答 (2 件)
Fangjun Jiang
2011 年 9 月 10 日
If it is just the matter of display, check doc format. try
format long g
2 件のコメント
Fangjun Jiang
2011 年 9 月 10 日
It is stored with the correct precision. If you want to store it in text file, you can use fprintf() or sprintf(), for example, string=sprintf('%15.6f',TRPfeat(1,1))
Check doc sprintf for details. It's pretty much the same as in C code.
Walter Roberson
2011 年 9 月 10 日
It is not possible with binary floating point numbers to exactly store values that have 6 digits after the decimal point (well, there are a small number that can be stored exactly but not many.)
If you take the values and multiply them by 10^6, round() that, and divide by 10^6, the result will be a matrix that will have the closest possible binary floating point numbers to the ones with 6 digits after the decimal point.
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