what will be the solution for this error

1 回表示 (過去 30 日間)
Poonam
Poonam 2014 年 9 月 12 日
編集済み: Pierre Benoit 2014 年 9 月 12 日
function idx=nomc(meas)
W=SimilarMatrix(meas,1);
D=diag(sum(W));
L=D-W;
Lsym=(D^(-1/2))*L*(D^(-1/2));
[ev ed]=eig(Lsym);
d=diag(ed); %#ok<NASGU>
V=ev(:,1:3);
for i=1:250
for j=1:7
U(i,j)=V(i,j)/sqrt(sum(V(i,:).^2)); %#ok<AGROW>
end
end
idx=kmeans(U,3);
figure;plot(idx);
result=[length(find(idx==1)),length(find(idx==2)),length(find(idx==3))];
getting error
??? Attempted to access V(1,4); index out of bounds because
size(V)=[143,3].
Error in ==> nomc at 11
U(i,j)=V(i,j)/sqrt(sum(V(i,:).^2)); %#ok<AGROW>
Error in ==> Normalizemeanseg at 120
f=nomc(y);
  2 件のコメント
Rushikesh Tade
Rushikesh Tade 2014 年 9 月 12 日
can you provide "meas" variable in mat format or provide dimensions?
Poonam
Poonam 2014 年 9 月 12 日
meas is <143x256x3 double>

サインインしてコメントする。

回答 (1 件)

Titus Edelhofer
Titus Edelhofer 2014 年 9 月 12 日
Hi,
you write
V = ev(:, 1:3);
so V has three columns. But your loop on j is
for j=1:7
That doesn't match ...
Titus
  4 件のコメント
Image Analyst
Image Analyst 2014 年 9 月 12 日
Poonam, I think you're mistaken. If the error says
Attempted to access V(1,4);
and your code is
for j=1:3
Then there is no way the second index of V could be 4 in this line
U(i,j)=V(i,j).....
Pierre Benoit
Pierre Benoit 2014 年 9 月 12 日
編集済み: Pierre Benoit 2014 年 9 月 12 日
Well, my guess was that this is no longer j that was causing a problem but i since the boundary of this loop is also quite arbitrary. And, maybe the author forgot to tell us or didn't see that the error changed a little.
But at this point, we can only guess given how little information we have.

サインインしてコメントする。

カテゴリ

Help Center および File ExchangeImage Processing Toolbox についてさらに検索

製品

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by