Simple help needed with identity matrices and selection

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Tanner
Tanner 2014 年 9 月 9 日
編集済み: José-Luis 2014 年 9 月 9 日
I'm just starting out in MATLAB and doing some homework for a class. What I'm trying to do is select the top-right and bottom-left quadrants of a 6x6 identity matrix and turn those smaller quadrants into identity matrices of themselves without inputting the elements individually. This is the best I could come up with, but clearly the quadrants I'm trying to select just turn into ones instead of identity matrices.
>> A=eye(6,6)
A =
1 0 0 0 0 0
0 1 0 0 0 0
0 0 1 0 0 0
0 0 0 1 0 0
0 0 0 0 1 0
0 0 0 0 0 1
>> A(1:3,4:6)=eye; A(4:6,1:3)=eye
A =
1 0 0 1 1 1
0 1 0 1 1 1
0 0 1 1 1 1
1 1 1 1 0 0
1 1 1 0 1 0
1 1 1 0 0 1
any help would be greatly appreciated!
  1 件のコメント
Tanner
Tanner 2014 年 9 月 9 日
Nevermind I just figured it out! If anyone is wondering the problem was that in my second command I should have input:
>>A(1:3,4:6)=eye(3,3);A(4:6,1:3)=eye(3,3)

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回答 (1 件)

José-Luis
José-Luis 2014 年 9 月 9 日
編集済み: José-Luis 2014 年 9 月 9 日
Almost there:
A=eye(6,6);
A(1:3,4:6)=eye(3); A(4:6,1:3)=eye(3);
eye without arguments returns 1.

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