sum of vector by group
2 ビュー (過去 30 日間)
古いコメントを表示
i have a vector of numbers
a=[1 4 1 -3 -6 9 9 1 1 1 -1 -1 -4]
and i group them by their sign (i don't have zero, only positive and negative number); 3 positive, 2 negative, ext. so:
b=[3 2 5 3]
now i want to find the sum of each group:
res=[6 -9 21 -6]
how can i do it, without using a loop.
Note: the vector "a" can be empty, contain only positive number, only negative number, or both of them when the first number can be positive or negative. in any case it don't contain zeros.
Note2: the way i find "b" is:
b = diff([1 find(diff([0 sign(a)]==1)~=0) length(a)+1]);
b=b(b~=0);
0 件のコメント
採用された回答
Sean de Wolski
2014 年 9 月 3 日
編集済み: Sean de Wolski
2014 年 9 月 3 日
a=[1 4 1 -3 -6 9 9 1 1 1 -1 -1 -4];
idx = cumsum([0 abs(diff(sign(a)))==2])+1;
res = accumarray(idx.',a.')
その他の回答 (0 件)
参考
カテゴリ
Help Center および File Exchange で Logical についてさらに検索
製品
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!