How to print result in MATLAB?

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Phan
Phan 2014 年 8 月 21 日
コメント済み: Phan 2014 年 8 月 21 日
Dear everyone,
Please help me to solve this problem. I have two arrays like this:
Name=['ABC-8' 'S8' 'EG8'];
Thick=[25 16 12];
I want to create an array like this:
Z=['ABC-825' 'S816' 'EG812'];
Can anyone help me to write a code to make that array?
Thank you so much!

採用された回答

Aniruddha Phatak
Aniruddha Phatak 2014 年 8 月 21 日
Robert is right, you must define it as a cell array.
name={'ABC-8' 'S8' 'EG8'};
thick=[25 16 12];
for i=1:3
thin{i} = [ num2str( thick(i) ) ];
z{i} = strcat(name{i},thin{i});
end
disp(z);

その他の回答 (3 件)

David Sanchez
David Sanchez 2014 年 8 月 21 日
define your Name array as a cell, then:
Name={'ABC-8' 'S8' 'EG8'};
Thick=[25 16 12];
Z =cell(numel(Name),1);
for k=1:numel(Name)
Z{k} = strcat(Name{k},num2str(Thick(k)));
end
>> Z
Z =
'ABC-825'
'S816'
'EG812'
  1 件のコメント
Phan
Phan 2014 年 8 月 21 日
Thank you so much!

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Guillaume
Guillaume 2014 年 8 月 21 日
編集済み: Guillaume 2014 年 8 月 21 日
Assuming that Name is a cell array, that is
Name = {'ABC-8' 'S8' 'EG8'};
(otherwise as you wrote it, it's just a single string). Then:
Z = cellfun(@(s,n) sprintf('%s%d', s, n), Name, num2cell(Thick), 'UniformOutput', false);
will do it. Note that Z has to be a cell array.
  1 件のコメント
Phan
Phan 2014 年 8 月 21 日
Thank you so much!

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Robert Cumming
Robert Cumming 2014 年 8 月 21 日
The two answers on here are correct - however if you take the for loop from one and the sprintf from the other you get a faster result:
Z =cell(1,numel(Name));
for k=1:numel(Name)
Z{k} = sprintf ( '%s%d', Name{k}, Thick(k) );
end
Speed evidence:
clear
clc
Name={'ABC-8' 'S8' 'EG8'};
Thick=[25 16 12];
tic
ZA =cell(1,numel(Name));
for k=1:numel(Name)
ZA{k} = strcat(Name{k},num2str(Thick(k)));
end
toc
tic
ZB = cellfun(@(s,n) sprintf('%s%d', s, n), Name, num2cell(Thick), 'UniformOutput', false);
toc
tic
ZC =cell(1,numel(Name));
for k=1:numel(Name)
ZC{k} = sprintf ( '%s%d', Name{k}, Thick(k) );
end
toc
isequal ( ZA, ZB )
isequal ( ZA, ZC )
Elapsed time is 0.011248 seconds.
Elapsed time is 0.011344 seconds.
Elapsed time is 0.006111 seconds.
  3 件のコメント
Robert Cumming
Robert Cumming 2014 年 8 月 21 日
For this type of question you could solve it in many ways....
I just highlight this as many people overlook the simple for loop and the fact that sprintf is the fastest way for handling strings...
Phan
Phan 2014 年 8 月 21 日
Thank you all! You helped so much!

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