Create a function to find the average of an entire matrix only using loops

I need to create a function only using loops (preferably only the for loop) to find the average of an inputted matrix. I am a novice at MATLAB so I really need help with this. So far, I can get the sum of the matrix using this:

 function outsum = mymatsum(mat)
 [row col] = size(mat);
 outsum = 0;
 for i = 1:row
    for j = 1:col
        outsum = outsum + mat(i,j);
    end
end

I need to be able to use something similar to get the average of the entire matrix. It needs to be a single number, not an array.

Answer 1

[Matt Tearle]

Why the requirement for a loop? The neatest way to do this is:

mean(x(:))

But if you really want a loop,

function y = matrixmean(x)
n = numel(x);
tot = 0;
for k=1:n
  tot = tot + x(k);
end
y = tot/n;

Note the use of a "linear index" for the matrix (ie one index value instead of two).

[Matt Tearle]

or, failing that, just modify what you already have for the sum, and divide the final answer by (row*col)

[Paulo Silva]

I was going to post this outsum/numel(mat) but Matt was faster :( (numel(mat)=row*col)

Answer 2

[zeeshan shafiq]

Lets try like this

% x=[1 4 5 7 8 9 3];

% N=[3 4 12 34 54 56 6];

clear

clc

function ave=myaverage(x,N)

sizex=size(x);

sizeN=size(N);

if sizex(2)~=sizeN(2)

beep

disp('Error')

else

total= sum(N);

s=x.*N;

ave=sum(s)/total;

end

end