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Copying option structs by value instead of reference

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Jonathan Epperl
Jonathan Epperl 2014 年 8 月 18 日
編集済み: per isakson 2014 年 8 月 18 日
Here is an example using bodeoptions, but this is probably a much more basic problem:
% Create a struct with default values
opt1 = bodeoptions;
% Change a value
opt1.MagScale = 'log'
% Now generate another (?) struct with the same options
opt2 = opt1;
% Change the value in the original struct back to default
opt1.MagScale = 'linear'
% Surprise! The value is changed back in the 'copy,' too
opt2.Magscale
Similarly, changing anything in opt2 changes opt1, too, so it appears opt2 is not another struct but a reference to the same structure as opt1.
Can anybody tell me what's happening here, and in particular: How would I create a copy of opt1 that I can change without changing opt1, too?

採用された回答

Guillaume
Guillaume 2014 年 8 月 18 日
Most likely, bodeoptions returns a handle class rather than a structure.
whos opt1
would tell you.
Matlab does not have a built-in way to do deep copy of handle classes. Possibly, the class has a method to do this. You can check with
methods(opt1)
But in any case, what's stopping you from creating your second variable with:
opt2 = bodeoptions;
It'll start out the same as opt1 but will be a different object.
  6 件のコメント
Jonathan Epperl
Jonathan Epperl 2014 年 8 月 18 日
With 2014a, I get
>> superclasses(opt1)
No class plotopts.BodePlotOptions
:(

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その他の回答 (1 件)

Image Analyst
Image Analyst 2014 年 8 月 18 日
Very interesting. It doesn't happen with simpler structures you make on your own:
s1.a = 10;
s1.b = 20;
% Make copy.
s2 = s1
% Change something in the original.
s1.a = 999
% Print to command window;
s1
s2 % s2.a is not 999

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