Use a variable with a file extenstion to load files

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David
David 2014 年 8 月 14 日
コメント済み: David 2014 年 8 月 14 日
Hi,
I Have 51 files in their own directory all of .out extention created by a seperate program, all numbered 0 to 50.
ie
0.out
1.out
2.out
and so on til 50.out.
I need to load each file 1 by one to do calculations upon them within a for loop. How would I do this using the count variable to load the file, if the directory is set beforehand?
i.e.
%set directiory
cd(......)
%for loop
For count = 0:50,
data = count.out *<-----this line*
.....
Many thanks!

採用された回答

Chad Greene
Chad Greene 2014 年 8 月 14 日
You can use sprintf or num2str. num2str is easier to use, but sprintf gives many more options including leading zeros.
  2 件のコメント
Chad Greene
Chad Greene 2014 年 8 月 14 日
data = load([num2str(count),'.out']);
David
David 2014 年 8 月 14 日
thanks:)

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