How to replace every value with the index of the value to the left of it
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This way the left most column is 0. I initially tried using a while loop but with a really big matrix, it takes way too long. so if I had a matrix
x= [ 2 3 4 5 6 ;
8 9 10 11 12 ]
the matrix i would want is
[ 0 1 3 5 7 9;
0 2 4 6 8 10 ]
I'm kind of at a crossroads here.
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