Simple Linear Interpolation using Interp1

174 ビュー (過去 30 日間)
Michael
Michael 2014 年 8 月 14 日
コメント済み: Peter 2024 年 4 月 23 日 12:54
Hi all. I'm fairly new to Matlab and I'm just trying to interpolate.
I have a [1 12] time vector that represent 12 hours. I also have a temperature vector that only has 10 values because 2 of them are missing. I understand that the sizes must be equal to use interp1. This is what I have so far:
time = [1 2 3 4 5 6 7 8 9 10 11 12];
temp = [10 12 15 13 [] 16 16 18 [] 15 21 20];
points = [1 2 3 4 5 6 7 8 9 10 11 12];
y = interp1(time,temp,points,'linear')
The empty matrices are where I don't have available times. I'm trying to use all of this data to linearly interpolate temperatures for all entries in my points array.
Thanks so much :)

採用された回答

Andrei Bobrov
Andrei Bobrov 2014 年 8 月 14 日
編集済み: Andrei Bobrov 2014 年 8 月 14 日
time = [1 2 3 4 6 7 8 10 11 12];
temp = [10 12 15 13 16 16 18 15 21 20];
points = [1 2 3 4 5 6 7 8 9 10 11 12];
y = interp1(time,temp,points,'linear');
  5 件のコメント
Gem
Gem 2022 年 11 月 19 日
May I have a question, is it possible to interpolate the data (NaN) if the x and y does have the same length in 3D plot.
Thank you !
Peter
Peter 2024 年 4 月 23 日 12:54
Thank you from 10 years later!

サインインしてコメントする。

その他の回答 (0 件)

カテゴリ

Help Center および File ExchangeInterpolation についてさらに検索

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by