フィルターのクリア

Loop only storing last run in nested for loop ... should be easy indixing easy for the experienced eye

1 回表示 (過去 30 日間)
This is a bit complex to explain without an essay but in point form, I have:
A large matrix with two parameters for 6 heights I want to bin the data by one parameter and then store this data in a struct for each bin I then was to do this for each height
The data is arranged in the following order date x y x2 y2 x3 y3 ... where the different levels represent the parameters at different heights.
Here is the code I have thus for but the loop is making the structure of the struct (names etc) perfectly but not iteratively saving the data:
inpdata = tower_wind_GF_allyrs;
inpdata = inpdata(~any(isnan(inpdata),2),:);
inpdata = inpdata(~any(isinf(inpdata),2),:);
bin = 0:0.51444:40;%maxws;
names = strtrim(cellstr(num2str([1:(length(bin)-1)]'))');
names = strrep(strcat('bin',names),'.','');
names2 = {'height10m' 'height20m' 'height40m' 'height80m' 'height120m' 'height200m'};
ind = cell(6,(length(bin)-1));
for k = linspace(2,12,6)
for l = linspace(3,13,6)
for i = 1:(length(bin)-1)
for varname = 1:length(names2)
search = find(inpdata(:,k) >= bin(i) & inpdata(:,k) < bin(i+1));
ind{varname,i} = search
binned_wind_allyrs.(names2{1,varname}).(names{1,i}) = cell(1,(length(bin)-1));
binned_wind_allyrs.(names2{1,varname}).(names{1,i}) = [inpdata(ind{varname,i}(:,1),k),inpdata(ind{varname,i}(:,1),l)];
end
end
end
end
Would LOVE to figure this out. Thanks in advance

採用された回答

Kelly Kearney
Kelly Kearney 2014 年 8 月 6 日
編集済み: Kelly Kearney 2014 年 8 月 6 日
You could simplify the syntax quite a bit using histc and accumarray:
inpdata = [datenum(2014,1,1)+(1:100)' rand(100,12)*39];
nheight = (size(inpdata,2)-1)/2;
bin = 0:0.51444:40;
nbin = length(bin);
xdata = inpdata(:,2:2:end);
ydata = inpdata(:,3:2:end);
% Bin the data
[n, idx] = histc(xdata, bin);
idx(idx == nbin+1) = nbin;
bindata = cell(nbin, nheight);
for ii = 1:nheight
x = accumarray(idx(:,ii), xdata(:,ii), [nbin 1], @(x) {x});
y = accumarray(idx(:,ii), ydata(:,ii), [nbin 1], @(x) {x});
bindata(:,ii) = cellfun(@(x,y) [x y], x, y, 'uni', 0);
end
% Structure output
bname = cellstr(num2str((1:nbin)', 'bin%02d'));
hname = {'height10m' 'height20m' 'height40m' 'height80m' 'height120m' 'height200m'};
for ib = 1:nbin
for ih = 1:nheight
S.(bname{ib}).(hname{ih}) = bindata{ib,ih};
end
end
  7 件のコメント
Kelly Kearney
Kelly Kearney 2014 年 8 月 18 日
Empty bins are not a problem. But data points that don't fit into a bin are. You have NaNs in your dataset, and histc assigns those data points to bin zero. So you'll have to decide what you want to do with those data points. This modification to the code above throws out any points where the x-data is NaN (it seems you have several data points with a valid x but NaN y; those points are left alone).
bindata = cell(nbin, nheight);
for ii = 1:nheight
isn = isnan(xdata(:,ii));
xtmp = xdata(~isn,ii);
ytmp = ydata(~isn,ii);
x = accumarray(idx(~isn,ii), xtmp, [nbin 1], @(x) {x});
y = accumarray(idx(~isn,ii), ytmp, [nbin 1], @(x) {x});
bindata(:,ii) = cellfun(@(x,y) [x y], x, y, 'uni', 0);
end
mashtine
mashtine 2014 年 8 月 26 日
Sorry for the late reply Kelly. Thank you very much for this!
Have a great week

サインインしてコメントする。

その他の回答 (1 件)

Iain
Iain 2014 年 8 月 6 日
Simple answer is on the left hand side, you need to index with k, l, i and varname.
So, this ought to work:
binned_wind_allyrs(k,l,i,varname) = {[inpdata(ind{varname,i}(:,1),k),inpdata(ind{varname,i}(:,1),l)]};
But you might need
binned_wind_allyrs(k,l,i,varname, 1:(numel(bin)-1)) = {[inpdata(ind{varname,i}(:,1),k),inpdata(ind{varname,i}(:,1),l)]};
  1 件のコメント
mashtine
mashtine 2014 年 8 月 7 日
Like this you mean:
binned_wind_allyrs(k,l,i,varname, 1:(numel(bin)-1)).(names2{1,varname}).(names{1,i}) = [inpdata(ind{varname,i},k),inpdata(ind{varname,i},l)];
When I put this, I am getting the following:
Scalar index required for this type of multi-level indexing.

サインインしてコメントする。

カテゴリ

Help Center および File ExchangeIntroduction to Installation and Licensing についてさらに検索

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by