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Solving a first order ODE using the Euler backward method (implicit)

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Ibrahim Ali
Ibrahim Ali 2021 年 10 月 1 日
閉鎖済み: Cris LaPierre 2021 年 10 月 1 日
I'm trying to solve a first order ODE with the initial condition y(5) = 0. To do this, I'm using the Euler backward method, but I'm getting these two errors:
Error using fzero (line 214)
Second argument must be finite.
Error in backwardeuler (line 22)
y(i+1) = fzero(@(Y) y(i) + dt*((2*t(i+1)-4)*exp(-Y)) - Y, y(i), options);
------------------------------------------------------------------------------------
% y_true = log(t^2 -4*t-4); Initial condition y(5) = 0;
% F_ty = @(t,y) (2*t-4)*exp(-y);
dt = 0.01;
t0 = 0;
tf = 3;
t = t0:dt:tf;
y(5) = 0;
% using the formula for backward euler: y(i+1) = y(i) + dt*f(y(i+1),t(i+1))
% we get
%y(i+1) = y(i) + dt*((2*t(i+1)-4)*exp(-y(i+1)));
% setting the LHS equal to zero so we can use fsolve:
% 0 = y(i) + dt*((2*t(i+1)-4)*exp(-y(i+1))) - y(i+1);
% We define y(i+1) = Y, so that
% 0 = y(i) + dt*((2*t(i+1)-4)*exp(-Y)) - Y;
options = optimset('TolX',1e-06);
for i = 1:length(t)-1
y(i+1) = fzero(@(Y) y(i) + dt*((2*t(i+1)-4)*exp(-Y)) - Y, y(i), options);
y_exact(i+1) = log((t(i+1))^2-4*t(i+1)-4);
end
figure(1)
hold on
plot(t,y,'bo')
plot(t,y_exact,'r-')
xlabel('time')
ylabel('y(t)')
title('Backward Euler method vs exact solution')
legend('Backward Euler', 'Exact')

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